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Shadow Theory

Feedback and Robust Local Readout of a Fixed Four-State Quantum Source

Robust readers: a convex-hull theorem and a global copy lower bound

Jeremy RodgersSection 7 of 15Original PDF ↗Publication DOI ↗

Robust readers: a convex-hull theorem and a global copy lower bound

We remove the repeated-angle restriction at one and two copies. The larger-horizon robust optimum remains unresolved; no fixed-angle optimum is silently promoted to it.

A general antipodal composite-source theorem

Let S be a nonempty compact subset of the equatorial Bloch disk. A hidden r ∈S and sign s ∈{+1, −1} are fixed throughout an experiment, and the source supplies independent copies of ρs,r = (I + s r · σ)/2. The reader cannot inspect the source label or nuisance register. On each copy it may choose any equatorial projective direction, followed by independent sign-blind erasure of fixed unknown efficiency η ∈[η0, 1], 0 < η0 ≤1. It must decide s at a fixed deadline, retaining all settings and nulls. Randomized policies and arbitrary terminal decision rules are admitted. The worst error takes a supremum over (s, r, η), without imposing a nuisance prior. Let z be the closest point to the origin in conv S and m = ∥z∥. Compactness ensures existence. The supporting-plane property is r · z ≥m2 (r ∈S). (1)

Theorem 6.1 (Global robust equality through two copies). In this complete equatorial policy class, the adaptive and randomized nonadaptive minimax values at horizons one and two are exactly

e1 = 1 −η0m
2
,
e2 = 1 −η0(2 −η0)m
2
.
Source page 14.
Searchable transcription
e1 = 1 −η0m
2
,
e2 = 1 −η0(2 −η0)m
2
.

For m > 0, repeating the single direction z/m and deciding by majority of nonnull signs with a fair tie attains both values. For m = 0, an uninformed fair decision attains 1/2 and neither class improves it. The same statement for a general three-dimensional Bloch set requires full Bloch-sphere projective access, not merely the equatorial menu.

Proof. The minimum-distance projection inequality gives (1), so measuring z/m has target-aligned bias at least m on every admitted source. At one copy its worst error is at most (1 −η0m)/2. At two copies majority with a fair tie has sign bias m whenever at least one copy survives erasure, giving the stated upper bound. These bounds are valid for unknown fixed r and unknown fixed η, and use one controller policy for all their values. For the lower bound, choose a finitely supported distribution μ on S with barycentre z; planar Carathéodory gives at most three support points. This distribution is a mathematical least-favourable comparison, not a new prior assumed by the robust protocol. Choose a fair source sign and efficiency η0. Each sampled r remains fixed for all copies. Define the two conditional target mixtures

Ω(n)
s
=
∫︂
S
ρ⊗n
s,r dμ(r).
Source page 14.
Searchable transcription
Ω(n)
s
=
∫︂
S
ρ⊗n
s,r dμ(r).
At one copy Ω(1)
+ −Ω(1)
−= z · σ, whose trace distance is m. At two copies, expanding each tensor
product gives
Ω(2)
+ −Ω(2)
−= 1
2{(z · σ) ⊗I + I ⊗(z · σ)}.
(2)
Technical passage, source page 14.
Searchable transcription
At one copy Ω(1)
+ −Ω(1)
−= z · σ, whose trace distance is m. At two copies, expanding each tensor
product gives
Ω(2)
+ −Ω(2)
−= 1
2{(z · σ) ⊗I + I ⊗(z · σ)}.
(2)
All quadratic terms cancel between opposite signs. Its eigenvalues are m, 0, 0, −m, so the two-copy
trace distance is again m. This calculation uses the mixture of tensor powers with fixed r; it never
substitutes the tensor power of a one-copy mixture.
An orthogonal auxiliary null flag simulates the complete declared classical outcome kernel. For
any fixed adaptive policy this simulation extends inductively over its histories and independent coins.
We may therefore lower-bound the policy by allowing arbitrary joint measurement of the auxiliary
states. At two copies the orthogonal zero-, one- and two-click blocks have total probability (1 −η0)2,
2η0(1 −η0) and η2
0. Their trace distances are 0, m, m. Thus the total trace distance is η0(2 −η0)m;
the one-copy value is η0m. Binary equal-prior minimum error (1 −D)/2 supplies the matching Bayes
lower bounds. A robust worst error cannot be smaller than any valid comparison-prior average. This
proves minimax equality. If m = 0, the same comparison makes both differences vanish.
Technical passage, source page 14.
Searchable transcription
All quadratic terms cancel between opposite signs. Its eigenvalues are m, 0, 0, −m, so the two-copy
trace distance is again m. This calculation uses the mixture of tensor powers with fixed r; it never
substitutes the tensor power of a one-copy mixture.
An orthogonal auxiliary null flag simulates the complete declared classical outcome kernel. For
any fixed adaptive policy this simulation extends inductively over its histories and independent coins.
We may therefore lower-bound the policy by allowing arbitrary joint measurement of the auxiliary
states. At two copies the orthogonal zero-, one- and two-click blocks have total probability (1 −η0)2,
2η0(1 −η0) and η2
0. Their trace distances are 0, m, m. Thus the total trace distance is η0(2 −η0)m;
the one-copy value is η0m. Binary equal-prior minimum error (1 −D)/2 supplies the matching Bayes
lower bounds. A robust worst error cannot be smaller than any valid comparison-prior average. This
proves minimax equality. If m = 0, the same comparison makes both differences vanish.

This establishes a concrete interface where feedback and additional settings are unnecessary: through two copies, the closest point of the positive-target Bloch hull supplies a sufficient robust reader direction. It is a statistical decision result, not complete retained-instrument identification. Correlated accessible preparation records, a readable purifier, non-independent copies or a different erasure parent change the task. The trace-distance decision principle is established quantum theory; the composite-source cancellation and its application to the specified reader task are proved here.

Applying the theorem to asymmetric fixed calibration

The preceding detector kernels have the following equivalent statistical Bloch set for a positive sign:

S = {g(cos δ, −sin δ) : g ∈[a, 1], |δ| ≤∆} ∪{g(sin δ, cos δ) : g ∈[b, 1], |δ| ≤∆}.
Source page 14.
Searchable transcription
S = {g(cos δ, −sin δ) : g ∈[a, 1], |δ| ≤∆} ∪{g(sin δ, cos δ) : g ∈[b, 1], |δ| ≤∆}.

Indeed the X source gives gX cos(θ + δ) and the Y source gives gY sin(θ + δ) when paired with nθ. Absorbing fixed nuisance into this set is a representation of the admitted classical kernels and decision risks. It neither identifies complete residual channels nor makes the nuisance accessible to the controller. Define u = (a cos ∆, −a sin ∆), v = (−b sin ∆, b cos ∆).

They are admitted positive-target vectors: choose gain floors, with δ = +∆on X and δ = −∆on Y. For the lower-bound prior this nuisance is correlated with the fixed hidden axis, and remains fixed throughout that experiment. This is allowed in the supremum over source label and nuisance; it is not a per-node adversary or a claim that a physical random calibration law follows that prior. Put c = u · v = −ab sin 2∆. The closest point on their segment is

z = pu + (1 −p)v,
p =
b2 −c
a2 + b2 −2c,
∥z∥= m∗=
ab cos 2∆
√
a2 + b2 + 2ab sin 2∆.
Source page 15.
Searchable transcription
z = pu + (1 −p)v,
p =
b2 −c
a2 + b2 −2c,
∥z∥= m∗=
ab cos 2∆
√
a2 + b2 + 2ab sin 2∆.

Here 0 < p < 1, and z · u = z · v = ∥z∥2. The preceding optimized direction has signal at least m∗on the whole uncertainty set, so the supporting-plane inequality also holds for all its other admissible vectors. Consequently z is closest in the whole hull, not only this segment. The global robust optima are therefore e1 = (1 −η0m∗)/2, e2 = (1 −η0(2 −η0)m∗)/2,

over every continuous equatorial adaptive or randomized nonadaptive reader. No common-positive restriction on competitors remains at these horizons. The attaining reader retains the robust angle

tan θ∗= a cos ∆+ b sin ∆
b cos ∆+ a sin ∆.
Source page 15.
Searchable transcription
tan θ∗= a cos ∆+ b sin ∆
b cos ∆+ a sin ∆.
For η0 = 4/5, a = 9/10, b = 4/5, tan ∆= 1/100, one obtains p = 654464/1478945, m2
∗=
129574081296/369773223625 and errors approximately 0.26321655725 and 0.21585986870. These are
global small-horizon values, not a claim about the one-percent threshold or unrestricted collective
readers in a different physical parent.
Technical passage, source page 15.
Searchable transcription
For η0 = 4/5, a = 9/10, b = 4/5, tan ∆= 1/100, one obtains p = 654464/1478945, m2
∗=
129574081296/369773223625 and errors approximately 0.26321655725 and 0.21585986870. These are
global small-horizon values, not a claim about the one-percent threshold or unrestricted collective
readers in a different physical parent.
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