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Shadow Theory

Feedback and Robust Local Readout of a Fixed Four-State Quantum Source

Frozen-angle randomization and preparation convexification

Jeremy RodgersSection 9 of 15Original PDF ↗Publication DOI ↗

Frozen-angle randomization and preparation convexification

A common least-favourable comparison for every horizon

For general positive gain floors a, b ≤1, efficiency floor η0 > 0 and 0 ≤∆< π/4, let

u = (a cos ∆, −a sin ∆), v = (−b sin ∆, b cos ∆), c = u · v = −ab sin 2∆.

The admitted hard comparison fixes X at its worst positive offset and Y at its worst negative offset, with gain floors and efficiency η0. A mathematical comparison prior may correlate its fixed nuisance with the fixed source axis; it is a lower-bound device for the supremum over source/nuisance pairs, not a new physical calibration law. Put

p =
b2 −c
a2 + b2 −2c,
z = pu + (1 −p)v,
m = ∥z∥=
ab cos 2∆
√
a2 + b2 + 2ab sin 2∆.
Source page 19.
Searchable transcription
p =
b2 −c
a2 + b2 −2c,
z = pu + (1 −p)v,
m = ∥z∥=
ab cos 2∆
√
a2 + b2 + 2ab sin 2∆.
Then z = mnθ∗, where
tan θ∗= a cos ∆+ b sin ∆
b cos ∆+ a sin ∆.
Source page 19.
Searchable transcription
Then z = mnθ∗, where
tan θ∗= a cos ∆+ b sin ∆
b cos ∆+ a sin ∆.

The direction θ∗lies in the common-positive interval I = [∆, π/2 −∆].

Let qn(β) be the error of majority with a fair tie after n independent signs of positive bias β, including q0 = 1/2. Define the full deadline risk, with all erasures counted, by

B
∑︂
(︄
B
n
)︄
ηn(1 −η)B−nqn(β).
QB(η, β) =
n=0
Source page 20.
Searchable transcription
B
∑︂
(︄
B
n
)︄
ηn(1 −η)B−nqn(β).
QB(η, β) =
n=0
For k ≥0,
q′
2k+1(β) = −(2k + 1)
(︁2k
k
)︁
22k+1
(1 −β2)k,
q2k = q2k−1 (k ≥1).
Source page 20.
Searchable transcription
For k ≥0,
q′
2k+1(β) = −(2k + 1)
(︁2k
k
)︁
22k+1
(1 −β2)k,
q2k = q2k−1 (k ≥1).

Consequently QB(η, β) is decreasing and convex on β ∈[0, 1]. Its second derivative is nonnegative term by term; no numerical curvature test is used to establish the statement.

Theorem 8.1 (All-horizon random-frozen-angle optimum and spread penalty). Before a block, choose one random nominal angle Θ ∈I, independently of the hidden source and nuisance. Retain the seed, repeat that angle for all B trials, and allow any randomized terminal decoder using the full retained record. The exact robust minimax error in this class is QB(η0, m), attained by the deterministic angle θ∗and fair-tie majority. Every such randomized reader has robust worst error at least

QB(η0, m) + m[−∂βQB(η0, m)]E[1 −cos(Θ −θ∗)]
≥QB(η0, m) + 2m[−∂βQB(η0, m)]
π2
E[(Θ −θ∗)2].
Source page 20.
Searchable transcription
QB(η0, m) + m[−∂βQB(η0, m)]E[1 −cos(Θ −θ∗)]
≥QB(η0, m) + 2m[−∂βQB(η0, m)]
π2
E[(Θ −θ∗)2].

This is not an optimum over varying-angle schedules, adaptive control, angles outside I, or collective quantum access.

Proof. Choose the fair sign and axis probabilities p, 1−p of the fixed hard comparison above. Conditional on a seed angle θ, its two positive biases are βX = a cos(θ+∆) and βY = b sin(θ−∆), both nonnegative. On any retained word, each axis component’s positive/negative sign likelihood difference has the sign of the nonnull signed count. Therefore their positive mixture has the same sign. Majority with a fair tie is Bayes-optimal even for the axis mixture and even if every ordered sign/null record is accessible. Its conditional Bayes risk is

f(θ) = pQB(η0, βX) + (1 −p)QB(η0, βY ).
Source page 20.
Searchable transcription
f(θ) = pQB(η0, βX) + (1 −p)QB(η0, βY ).

Any other decoder has at least this comparison-prior average error. Convexity in the bias gives

f(θ) ≥QB(η0, pβX + (1 −p)βY ) = QB(η0, m cos(θ −θ∗)).
Source page 20.
Searchable transcription
f(θ) ≥QB(η0, pβX + (1 −p)βY ) = QB(η0, m cos(θ −θ∗)).
Because QB is decreasing and convex, its tangent at m lower-bounds the last expression by QB(η0, m)+
m[−Q′
B(η0, m)](1 −cos(θ −θ∗)). Average over the retained seed. The robust supremum is at least
this fixed comparison average. Finally 1 −cos x ≥2x2/π2 for |x| ≤π, by concavity of sine on [0, π/2].
The interval I ensures this range. The preceding frozen reader attains QB(η0, m) uniformly over the
original uncertainty set, proving the equality as well as the quantitative penalties.
Technical passage, source page 20.
Searchable transcription
Because QB is decreasing and convex, its tangent at m lower-bounds the last expression by QB(η0, m)+
m[−Q′
B(η0, m)](1 −cos(θ −θ∗)). Average over the retained seed. The robust supremum is at least
this fixed comparison average. Finally 1 −cos x ≥2x2/π2 for |x| ≤π, by concavity of sine on [0, π/2].
The interval I ensures this range. The preceding frozen reader attains QB(η0, m) uniformly over the
original uncertainty set, proving the equality as well as the quantitative penalties.
For the original example,
Source page 20.
Searchable transcription
For the original example,
p = 654464
1478945,
m2 = 129574081296
369773223625.
Source page 20.
Searchable transcription
p = 654464
1478945,
m2 = 129574081296
369773223625.

Exact quadratic-field arithmetic gives

Trials Robust random-frozen optimum One-percent status

15
.0124288300109 . . .
fails
16
.0102368487113 . . .
fails
17
.00844219845891 . . .
passes
Source page 21.
Searchable transcription
15
.0124288300109 . . .
fails
16
.0102368487113 . . .
fails
17
.00844219845891 . . .
passes

Hence seventeen is the exact minimum in the enlarged random-frozen class. A phase lottery is not a route to improving that threshold. Any improvement must use another interface, such as varying settings within a block, feedback, or additional information. This does not prove that a varying nonadaptive schedule needs seventeen, nor that adaptation is advantageous at one percent.

When convexification makes the frozen reader globally optimal

Theorem 8.2 (An all-horizon convex-source benchmark). Let S be a nonempty compact subset of the equatorial Bloch disk for the fixed antipodal source family ρs,r = (I + sr · σ)/2. Suppose its closest convex-hull point z is itself physically admissible: z ∈S. With independent copies conditional on fixed (s, r), independent sign-blind erasures η ≥η0 and a fixed deadline, both full continuous local adaptive and randomized nonadaptive minimax errors equal QB(η0, ∥z∥) for every B. One frozen direction z/∥z∥ attains it when z ̸= 0; the z = 0 value is 1/2.

Proof. The supporting-plane inequality r · z ≥∥z∥2 for every r ∈S makes the frozen direction’s sign bias at least ∥z∥. Majority risk is decreasing in positive bias and efficiency, giving the upper bound. For the lower bound, the actual pair ρ+,z, ρ−,z is admissible. Those states commute and are diagonal in the proposed measurement basis. Their independent tensor powers, including orthogonal erasure flags at η0, are a classical ternary likelihood problem. The likelihood ratio is monotone in the signed count, so even an arbitrary joint auxiliary-state measurement cannot beat fair-tie majority. This gives the same lower bound for every local protocol and its randomization. The zero vector has no sign information and gives 1/2.

The assumption z ∈S is essential to this proof. In the original asymmetric reader, the positive-target set consists of two separated near-axis regions and does not contain the diagonal point z. Replacing it by its physical convex hull would admit a new independent-copy mixed source. That is a different, explicitly enlarged preparation class, not a permitted replacement of the original fixed hidden axis. It provides an exact benchmark and identifies the preparation distinction that a more advanced reader would have to exploit.

A retained-record witness of the preparation distinction

For the original hard support u, v, let ρs,z = pρs,u + (1 −p)ρs,v. The actual fixed-axis mixture and independent copies of that averaged one-copy state differ at two copies:

Ω(2)
s
= pρ⊗2
s,u + (1 −p)ρ⊗2
s,v,
Ω(2)
s
−ρ⊗2
s,z = p(1 −p)
4
[(u −v) · σ] ⊗[(u −v) · σ].
Source page 21.
Searchable transcription
Ω(2)
s
= pρ⊗2
s,u + (1 −p)ρ⊗2
s,v,
Ω(2)
s
−ρ⊗2
s,z = p(1 −p)
4
[(u −v) · σ] ⊗[(u −v) · σ].

Put V = p(1 −p)∥u −v∥2. The trace distance is exactly V/2. Since z · (u −v) = 0, measuring each copy along n⊥= (u −v)/∥u −v∥gives sign-product expectation V in the fixed-axis mixture and zero in the independent averaged state. Coding a retained null as zero changes the difference to η2V under the same independent sign-blind erasure law. No click postselection is used. For the original parameters,

V = 134898283296
369773223625 ≃.364813552408,
η2
0V ≃.233480673541.
Source page 21.
Searchable transcription
V = 134898283296
369773223625 ≃.364813552408,
η2
0V ≃.233480673541.

This is a standard covariance identity given an explicit operational readout, not a new physical law or a solution of the sign target itself. It makes the distinction between the two preparation laws experimentally meaningful under trusted preparation and the specified access contract. The comparison-prior stock is not asserted to be the actual unknown source in every deployment.

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